Integrand size = 29, antiderivative size = 29 \[ \int x^m \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2 \, dx=\frac {10 b^2 c^2 d^2 x^{3+m} \sqrt {d-c^2 d x^2}}{(4+m)^3 (6+m)}+\frac {2 b^2 c^2 d^2 \left (52+15 m+m^2\right ) x^{3+m} \sqrt {d-c^2 d x^2}}{(4+m)^2 (6+m)^3}-\frac {2 b^2 c^4 d^2 x^{5+m} \sqrt {d-c^2 d x^2}}{(6+m)^3}-\frac {30 b c d^2 x^{2+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(2+m)^2 (4+m) (6+m) \sqrt {1-c^2 x^2}}-\frac {10 b c d^2 x^{2+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(6+m) \left (8+6 m+m^2\right ) \sqrt {1-c^2 x^2}}-\frac {2 b c d^2 x^{2+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{\left (12+8 m+m^2\right ) \sqrt {1-c^2 x^2}}+\frac {10 b c^3 d^2 x^{4+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(4+m)^2 (6+m) \sqrt {1-c^2 x^2}}+\frac {4 b c^3 d^2 x^{4+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(4+m) (6+m) \sqrt {1-c^2 x^2}}-\frac {2 b c^5 d^2 x^{6+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(6+m)^2 \sqrt {1-c^2 x^2}}+\frac {15 d^2 x^{1+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^2}{(6+m) \left (8+6 m+m^2\right )}+\frac {5 d x^{1+m} \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^2}{(4+m) (6+m)}+\frac {x^{1+m} \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2}{6+m}+\frac {30 b^2 c^2 d^2 x^{3+m} \sqrt {d-c^2 d x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3+m}{2},\frac {5+m}{2},c^2 x^2\right )}{(2+m)^2 (3+m) (4+m) (6+m) \sqrt {1-c^2 x^2}}+\frac {10 b^2 c^2 d^2 (10+3 m) x^{3+m} \sqrt {d-c^2 d x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3+m}{2},\frac {5+m}{2},c^2 x^2\right )}{(2+m) (3+m) (4+m)^3 (6+m) \sqrt {1-c^2 x^2}}+\frac {2 b^2 c^2 d^2 \left (264+130 m+15 m^2\right ) x^{3+m} \sqrt {d-c^2 d x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3+m}{2},\frac {5+m}{2},c^2 x^2\right )}{(2+m) (3+m) (4+m)^2 (6+m)^3 \sqrt {1-c^2 x^2}}+\frac {15 d^3 \text {Int}\left (\frac {x^m (a+b \arcsin (c x))^2}{\sqrt {d-c^2 d x^2}},x\right )}{(6+m) \left (8+6 m+m^2\right )} \]
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Not integrable
Time = 0.81 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int x^m \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2 \, dx=\int x^m \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2 \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {x^{1+m} \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2}{6+m}+\frac {(5 d) \int x^m \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^2 \, dx}{6+m}-\frac {\left (2 b c d^2 \sqrt {d-c^2 d x^2}\right ) \int x^{1+m} \left (1-c^2 x^2\right )^2 (a+b \arcsin (c x)) \, dx}{(6+m) \sqrt {1-c^2 x^2}} \\ & = -\frac {2 b c d^2 x^{2+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{\left (12+8 m+m^2\right ) \sqrt {1-c^2 x^2}}+\frac {4 b c^3 d^2 x^{4+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(4+m) (6+m) \sqrt {1-c^2 x^2}}-\frac {2 b c^5 d^2 x^{6+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(6+m)^2 \sqrt {1-c^2 x^2}}+\frac {5 d x^{1+m} \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^2}{(4+m) (6+m)}+\frac {x^{1+m} \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2}{6+m}+\frac {\left (15 d^2\right ) \int x^m \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^2 \, dx}{(4+m) (6+m)}+\frac {\left (2 b^2 c^2 d^2 \sqrt {d-c^2 d x^2}\right ) \int \frac {x^{2+m} \left (\frac {1}{2+m}-\frac {2 c^2 x^2}{4+m}+\frac {c^4 x^4}{6+m}\right )}{\sqrt {1-c^2 x^2}} \, dx}{(6+m) \sqrt {1-c^2 x^2}}-\frac {\left (10 b c d^2 \sqrt {d-c^2 d x^2}\right ) \int x^{1+m} \left (1-c^2 x^2\right ) (a+b \arcsin (c x)) \, dx}{(4+m) (6+m) \sqrt {1-c^2 x^2}} \\ & = -\frac {2 b^2 c^4 d^2 x^{5+m} \sqrt {d-c^2 d x^2}}{(6+m)^3}-\frac {10 b c d^2 x^{2+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(2+m) (4+m) (6+m) \sqrt {1-c^2 x^2}}-\frac {2 b c d^2 x^{2+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{\left (12+8 m+m^2\right ) \sqrt {1-c^2 x^2}}+\frac {10 b c^3 d^2 x^{4+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(4+m)^2 (6+m) \sqrt {1-c^2 x^2}}+\frac {4 b c^3 d^2 x^{4+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(4+m) (6+m) \sqrt {1-c^2 x^2}}-\frac {2 b c^5 d^2 x^{6+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(6+m)^2 \sqrt {1-c^2 x^2}}+\frac {15 d^2 x^{1+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^2}{(2+m) (4+m) (6+m)}+\frac {5 d x^{1+m} \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^2}{(4+m) (6+m)}+\frac {x^{1+m} \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2}{6+m}+\frac {\left (15 d^3\right ) \int \frac {x^m (a+b \arcsin (c x))^2}{\sqrt {d-c^2 d x^2}} \, dx}{(2+m) (4+m) (6+m)}-\frac {\left (2 b^2 d^2 \sqrt {d-c^2 d x^2}\right ) \int \frac {x^{2+m} \left (-\frac {c^2 (6+m)}{2+m}+\frac {c^4 \left (52+15 m+m^2\right ) x^2}{(4+m) (6+m)}\right )}{\sqrt {1-c^2 x^2}} \, dx}{(6+m)^2 \sqrt {1-c^2 x^2}}+\frac {\left (10 b^2 c^2 d^2 \sqrt {d-c^2 d x^2}\right ) \int \frac {x^{2+m} \left (\frac {1}{2+m}-\frac {c^2 x^2}{4+m}\right )}{\sqrt {1-c^2 x^2}} \, dx}{(4+m) (6+m) \sqrt {1-c^2 x^2}}-\frac {\left (30 b c d^2 \sqrt {d-c^2 d x^2}\right ) \int x^{1+m} (a+b \arcsin (c x)) \, dx}{(2+m) (4+m) (6+m) \sqrt {1-c^2 x^2}} \\ & = \frac {10 b^2 c^2 d^2 x^{3+m} \sqrt {d-c^2 d x^2}}{(4+m)^3 (6+m)}+\frac {2 b^2 c^2 d^2 \left (52+15 m+m^2\right ) x^{3+m} \sqrt {d-c^2 d x^2}}{(4+m)^2 (6+m)^3}-\frac {2 b^2 c^4 d^2 x^{5+m} \sqrt {d-c^2 d x^2}}{(6+m)^3}-\frac {30 b c d^2 x^{2+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(2+m)^2 (4+m) (6+m) \sqrt {1-c^2 x^2}}-\frac {10 b c d^2 x^{2+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(2+m) (4+m) (6+m) \sqrt {1-c^2 x^2}}-\frac {2 b c d^2 x^{2+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{\left (12+8 m+m^2\right ) \sqrt {1-c^2 x^2}}+\frac {10 b c^3 d^2 x^{4+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(4+m)^2 (6+m) \sqrt {1-c^2 x^2}}+\frac {4 b c^3 d^2 x^{4+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(4+m) (6+m) \sqrt {1-c^2 x^2}}-\frac {2 b c^5 d^2 x^{6+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(6+m)^2 \sqrt {1-c^2 x^2}}+\frac {15 d^2 x^{1+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^2}{(2+m) (4+m) (6+m)}+\frac {5 d x^{1+m} \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^2}{(4+m) (6+m)}+\frac {x^{1+m} \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2}{6+m}+\frac {\left (15 d^3\right ) \int \frac {x^m (a+b \arcsin (c x))^2}{\sqrt {d-c^2 d x^2}} \, dx}{(2+m) (4+m) (6+m)}+\frac {\left (30 b^2 c^2 d^2 \sqrt {d-c^2 d x^2}\right ) \int \frac {x^{2+m}}{\sqrt {1-c^2 x^2}} \, dx}{(2+m)^2 (4+m) (6+m) \sqrt {1-c^2 x^2}}+\frac {\left (10 b^2 c^2 d^2 (10+3 m) \sqrt {d-c^2 d x^2}\right ) \int \frac {x^{2+m}}{\sqrt {1-c^2 x^2}} \, dx}{(2+m) (4+m)^3 (6+m) \sqrt {1-c^2 x^2}}+\frac {\left (2 b^2 c^2 d^2 \left (264+130 m+15 m^2\right ) \sqrt {d-c^2 d x^2}\right ) \int \frac {x^{2+m}}{\sqrt {1-c^2 x^2}} \, dx}{(2+m) (4+m)^2 (6+m)^3 \sqrt {1-c^2 x^2}} \\ & = \frac {10 b^2 c^2 d^2 x^{3+m} \sqrt {d-c^2 d x^2}}{(4+m)^3 (6+m)}+\frac {2 b^2 c^2 d^2 \left (52+15 m+m^2\right ) x^{3+m} \sqrt {d-c^2 d x^2}}{(4+m)^2 (6+m)^3}-\frac {2 b^2 c^4 d^2 x^{5+m} \sqrt {d-c^2 d x^2}}{(6+m)^3}-\frac {30 b c d^2 x^{2+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(2+m)^2 (4+m) (6+m) \sqrt {1-c^2 x^2}}-\frac {10 b c d^2 x^{2+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(2+m) (4+m) (6+m) \sqrt {1-c^2 x^2}}-\frac {2 b c d^2 x^{2+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{\left (12+8 m+m^2\right ) \sqrt {1-c^2 x^2}}+\frac {10 b c^3 d^2 x^{4+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(4+m)^2 (6+m) \sqrt {1-c^2 x^2}}+\frac {4 b c^3 d^2 x^{4+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(4+m) (6+m) \sqrt {1-c^2 x^2}}-\frac {2 b c^5 d^2 x^{6+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))}{(6+m)^2 \sqrt {1-c^2 x^2}}+\frac {15 d^2 x^{1+m} \sqrt {d-c^2 d x^2} (a+b \arcsin (c x))^2}{(2+m) (4+m) (6+m)}+\frac {5 d x^{1+m} \left (d-c^2 d x^2\right )^{3/2} (a+b \arcsin (c x))^2}{(4+m) (6+m)}+\frac {x^{1+m} \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2}{6+m}+\frac {30 b^2 c^2 d^2 x^{3+m} \sqrt {d-c^2 d x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3+m}{2},\frac {5+m}{2},c^2 x^2\right )}{(2+m)^2 (3+m) (4+m) (6+m) \sqrt {1-c^2 x^2}}+\frac {10 b^2 c^2 d^2 (10+3 m) x^{3+m} \sqrt {d-c^2 d x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3+m}{2},\frac {5+m}{2},c^2 x^2\right )}{(2+m) (3+m) (4+m)^3 (6+m) \sqrt {1-c^2 x^2}}+\frac {2 b^2 c^2 d^2 \left (264+130 m+15 m^2\right ) x^{3+m} \sqrt {d-c^2 d x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3+m}{2},\frac {5+m}{2},c^2 x^2\right )}{(2+m) (3+m) (4+m)^2 (6+m)^3 \sqrt {1-c^2 x^2}}+\frac {\left (15 d^3\right ) \int \frac {x^m (a+b \arcsin (c x))^2}{\sqrt {d-c^2 d x^2}} \, dx}{(2+m) (4+m) (6+m)} \\ \end{align*}
Not integrable
Time = 9.76 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.07 \[ \int x^m \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2 \, dx=\int x^m \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2 \, dx \]
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Not integrable
Time = 5.47 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.93
\[\int x^{m} \left (-c^{2} d \,x^{2}+d \right )^{\frac {5}{2}} \left (a +b \arcsin \left (c x \right )\right )^{2}d x\]
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Not integrable
Time = 0.25 (sec) , antiderivative size = 134, normalized size of antiderivative = 4.62 \[ \int x^m \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2 \, dx=\int { {\left (-c^{2} d x^{2} + d\right )}^{\frac {5}{2}} {\left (b \arcsin \left (c x\right ) + a\right )}^{2} x^{m} \,d x } \]
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Timed out. \[ \int x^m \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2 \, dx=\text {Timed out} \]
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Not integrable
Time = 0.91 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00 \[ \int x^m \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2 \, dx=\int { {\left (-c^{2} d x^{2} + d\right )}^{\frac {5}{2}} {\left (b \arcsin \left (c x\right ) + a\right )}^{2} x^{m} \,d x } \]
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Exception generated. \[ \int x^m \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2 \, dx=\text {Exception raised: TypeError} \]
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Not integrable
Time = 0.25 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00 \[ \int x^m \left (d-c^2 d x^2\right )^{5/2} (a+b \arcsin (c x))^2 \, dx=\int x^m\,{\left (a+b\,\mathrm {asin}\left (c\,x\right )\right )}^2\,{\left (d-c^2\,d\,x^2\right )}^{5/2} \,d x \]
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